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416=2x^2-6x
We move all terms to the left:
416-(2x^2-6x)=0
We get rid of parentheses
-2x^2+6x+416=0
a = -2; b = 6; c = +416;
Δ = b2-4ac
Δ = 62-4·(-2)·416
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3364}=58$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-58}{2*-2}=\frac{-64}{-4} =+16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+58}{2*-2}=\frac{52}{-4} =-13 $
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